When I connect to a Bluetooth Device the only option I have is to enter a pin (all numbers)
But the device I want to pair to, requires a passcode (alpha numeric).

Is there anyway in Windows Phone to pair to that type of device without setting up a pin?

  • What's the Bluetooth device that you're trying to pair with?
    – Rowland Shaw
    Apr 15 '14 at 19:06
  • It is a 3rd party device I am developing against my client had built custom. We can talk to the developer and get PIN added I just wanted to see if there was some way to complete the paring with a code and I couldn't find any info. Apr 15 '14 at 21:40

It might be the case that the device doesn't support a compatible Bluetooth profile. I would expect the phone to automatically display a suitable keyboard, but I've not personally come across a Bluetooth device that required an alpha numeric pin (possibly due to manufacturers wanting compatibility with the widest range of devices).

The supported level of Bluetooth with Windows Phone 8.0 is Bluetooth 3.1, according to the Microsoft website:

Windows Phone 8 supports Bluetooth 3.1. This is an improved version of Bluetooth that automates the pairing process between Windows Phone 8 and Bluetooth devices, such as phone headsets, car audio systems, speaker docks, and NFC pairing.

Here are the Bluetooth user profiles that Windows Phone 8 supports:

  • Advanced Audio Distribution Profile (A2DP 1.2)
  • Audio/Video Remote Control Profile (AVRCP 1.4)
  • Hands Free Profile (HFP 1.5)
  • Phone Book Access Profile (PBAP 1.1)
  • Object Push Profile (OPP 1.1)
  • Out of Band (OOB) and Near Field Communications (NFC)

For a Bluetooth device or accessory to work with your phone, the device needs to use one of the supported profiles.

Windows Phone 8.1, due soon, is reported to support Bluetooth 4 (including the low energy variant)

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.